74x^2-60x+12=0

Solution for 74x^2-60x+12=0 equation:

74x^2-60x+12=0

a = 74; b = -60; c = +12;
Δ = b2-4ac
Δ = -602-4·74·12
Δ = 48
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{48}=\sqrt{16*3}=\sqrt{16}*\sqrt{3}=4\sqrt{3}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-60)-4\sqrt{3}}{2*74}=\frac{60-4\sqrt{3}}{148}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-60)+4\sqrt{3}}{2*74}=\frac{60+4\sqrt{3}}{148}
$